The Aluminium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Aluminium.
Al -> Al+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Aluminium is:
AlN+ -> Al(N+1)+ + e-
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Al -> Al1+ = 577.4 kJ/mol = 138.13 Kcal/mol
\nAl1+ -> Al2+ = 1816.6 kJ/mol = 434.59 Kcal/mol
\nAl2+ -> Al3+ = 2744.6 kJ/mol = 656.60 Kcal/mol
\nAl3+ -> Al4+ = 11575 kJ/mol = 2769.14 Kcal/mol
\nAl4+ -> Al5+ = 14839 kJ/mol = 3550.00 Kcal/mol
\nAl5+ -> Al6+ = 18376 kJ/mol = 4396.17 Kcal/mol
\nAl6+ -> Al7+ = 23293 kJ/mol = 5572.49 Kcal/mol
\nAl7+ -> Al8+ = 27457 kJ/mol = 6568.66 Kcal/mol
\nAl8+ -> Al9+ = 31857 kJ/mol = 7621.29 Kcal/mol
\nAl9+ -> Al10+ = 38459 kJ/mol = 9200.72 Kcal/mol
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